-0.008x^2+32x=0

Solution for -0.008x^2+32x=0 equation:

-0.008x^2+32x=0

a = -0.008; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-0.008)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-0.008}=\frac{-64}{-0.016}
=+4000
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-0.008}=\frac{0}{-0.016}
=0
$